Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    The electron in the lowest (n = 1) orbit in hydrogen atom has energy - 13.6 eV. How much energy is required to ionize a hydrogen atom which is already in the first excited level?

    A)  3.4 eV                                 

    B)  10.2 eV

    C)  13.6 eV                               

    D)  1.9 eV

    Correct Answer: A

    Solution :

    lonisation energy \[E=\frac{-13.6}{{{n}^{2}}}eV\] For first excited state \[n=2\] So,       \[E=\frac{-13.6}{{{2}^{2}}}=3.4eV\] \[=3.4\text{ }eV\] (numerically)


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