Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    One mole glucose, on complete oxidation, yields energy

    A)  686 cal                                 

    B)  68,600 cal

    C)  6,86,000 cal                       

    D)  68,60,000 cal

    Correct Answer: C

    Solution :

    In aerobic respiration, oxygen is used and it completely oxidises the organic food mainly carbohydrates (sugars) to carbon dioxide and water. It, therefore, releases the entire energy in the form of a glucose \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{12}}}{{\text{O}}_{\text{6}}}\text{+}\,\text{6}{{\text{0}}_{\text{2}}}\xrightarrow[{}]{{}}\text{6}\,\text{C}\,{{\text{O}}_{\text{2}}}\text{+}\,\text{6}\,\text{H}{{\,}_{\text{2}}}\text{O}\]+ Energy (686 kcal glucose)


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