A) \[C{{l}_{2}}\]
B) \[I_{3}^{\bigcirc -}\]
C) \[{{I}_{2}}\]
D) \[C{{l}^{\bigcirc -}}\]
Correct Answer: A
Solution :
\[C{{l}_{2}}\] is stronger reducing agent than \[B{{r}_{2}},\]hence chlorine replace \[B{{r}_{2}}\] from the aqueous solution having bromide ion. \[2NaBr+C{{l}_{2}}\xrightarrow{{}}2NaCl+B{{r}_{2}}\]
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