A) \[0.304\text{ }{{m}^{2}}\]
B) \[30.4\text{ }{{m}^{2}}\]
C) \[384\text{ }{{m}^{2}}\]
D) \[3.04\text{ }{{m}^{2}}\]
Correct Answer: B
Solution :
Now, using the relation \[r=\frac{h}{\sqrt{{{\mu }^{2}}-1}}\] or \[A=\pi {{r}^{2}}=\frac{\pi {{h}^{2}}}{{{\mu }^{2}}-1}\] \[=\frac{3.14\times {{(2.75)}^{2}}}{{{\left( \frac{4}{3} \right)}^{2}}-1}=30.4{{m}^{2}}\]
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