Haryana PMT Haryana PMT Solved Paper-2002

  • question_answer
    An iron piece fall from a height of 1 km on the    ground. If all the energy is converted into heat the rise of temperature of the iron piece will be (specific heat of iron = 0.1 k cal/kg° C)

    A) \[0.233{}^\circ C\]           

    B) \[2.33{}^\circ C\]

    C) \[23.8{}^\circ C\]

    D) \[233{}^\circ C\]

    Correct Answer: C

    Solution :

                    Kinetic energy = Heat \[\frac{1}{2}\frac{m{{\upsilon }^{2}}}{4.2}=ms\,\Delta \theta \] \[\frac{1}{2}\frac{m\,2gh}{4.2}=ms\,\Delta \theta \] \[\Rightarrow \]               \[\frac{mgh}{4.2}=ms\,\,\Delta \theta \]                 \[\frac{10\times 1000}{4.2}=0.1\times 1000\times \Delta \theta \]                 \[\Delta \theta ={{23.8}^{o}}C\]


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