A) 50 \[\Omega \]
B) 100 \[\Omega \]
C) 200 \[\Omega \]
D) 400 \[\Omega \]
Correct Answer: B
Solution :
When C is removed, circuit becomes R-L circuit. Hence, \[\tan \frac{\pi }{3}=\frac{{{X}_{L}}}{R}\] .....(i) When L is removed, circuit becomes R-C circuit. Hence, \[\tan \frac{\pi }{3}=\frac{{{X}_{C}}}{R}\] ?..(ii) From Eqs. (i) and (ii), we obtain \[{{X}_{L}}={{X}_{C}}\]; this is the condition of resonance \[\therefore \] \[Z=R=100\Omega \]
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