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J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    For the reaction, \[{{N}_{2}}+3{{H}_{2}}2NH;\Delta H=?\]

    A) \[\Delta E=+\,2RT\]

    B) \[\Delta E-\,2RT\]

    C)  \[\Delta E+\,RT\]

    D) \[\Delta E-\,RT\]

    Correct Answer: B

    Solution :

    \[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\] \[\Delta H=\Delta E+\Delta nRT\] \[\Delta n=2-4=-2\] \[\therefore \] \[\Delta \Eta =\Delta E+(-2)RT\] \[\Delta \Eta =\Delta E-2RT\]


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