2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2007

  • question_answer
    A particle moves from position \[3\hat{i}+2\hat{j}+6\hat{k}\] to \[14\hat{i}+13\hat{j}+9\hat{k}\] due to a uniform force of\[4\hat{i}+\hat{j}+3k\text{ }N\]. Find the work done, if the displacement is in metre.

    A)  \[16\text{ }J\]         

    B)  \[64\text{ }J\]

    C)  \[32\text{ }J\]         

    D)  \[48\text{ }J\]

    Correct Answer: B

    Solution :

    Work done \[=\vec{F}\,.\vec{d}\] \[=(4\hat{i}+\hat{j}+3\hat{k}).[(14-3)\hat{i}+(13-2)\hat{j}+(9-6)\hat{k}]\] \[=(4\hat{i}+\hat{j}+3\hat{k}).(11\hat{i}+11\hat{j}+3\hat{k})\] \[=44+11+9=64\,J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner