A) \[1\]
B) \[3\]
C) \[4\]
D) \[2\]
Correct Answer: C
Solution :
\[\left| \begin{matrix} x & y & z \\ -x & y & z \\ x & -y & z \\ \end{matrix} \right|\] \[=\left| \begin{matrix} x & y & z \\ -x & y & z \\ 0 & 0 & 2z \\ \end{matrix} \right|\] \[({{R}_{3}}\to {{R}_{3}}+{{R}_{2}})\] Expanding along \[{{R}_{3}},\] we get \[=2z(xy+xy)=4xyz\] On comparing with kxyz, we get \[k=4\]
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