A) \[\text{L}\,\,\text{at}{{\text{m}}^{\text{2}}}\,\text{mo}{{\text{l}}^{-1}}\]and \[\text{mo}{{\text{l}}^{-1}}\]
B) \[\text{L}\,\,\text{atm}\,\text{mo}{{\text{l}}^{2}}\]and \[\text{mol L}\]
C) \[{{\text{L}}^{2}}\,\,\text{atm}\,\text{mo}{{\text{l}}^{-2}}\]and \[\text{mo}{{\text{l}}^{-1}}\text{ L}\]
D) \[{{\text{L}}^{-2}}\,\,\text{at}{{\text{m}}^{-1}}\,\text{mo}{{\text{l}}^{-1}}\]and \[\text{L}\,\text{mo}{{\text{l}}^{-2}}\]
Correct Answer: C
Solution :
van der Waals' equation is \[\left( p+\frac{{{n}^{2}}a}{{{V}^{2}}} \right)(V-nb)=nRT\] \[\therefore \] Units of \[a=\frac{p{{V}^{2}}}{{{n}^{2}}}\] \[=\frac{\text{atm}\times {{L}^{2}}}{\text{mo}{{\text{l}}^{\text{2}}}}\] \[={{L}^{2}}\,\text{atm}\,\text{mo}{{\text{l}}^{-2}}\] \[\therefore \] Units of\[b=\frac{V}{n}\] \[=\frac{L}{mol}=\text{mo}{{\text{l}}^{-1}}L\]
You need to login to perform this action.
You will be redirected in
3 sec
