A) \[1:2\]
B) \[4:1\]
C) \[1:16\]
D) \[1:4\]
Correct Answer: D
Solution :
The magnitude of the viscous force depends on the shape and size of the body, its speed and the viscosity of the fluid. Stokes established that if a sphere of radius r moves with velocity v through a fluid of viscosity y{, the viscous force opposing the motion of the sphere \[F=6\pi \eta rv\] \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{{{r}_{1}}}{{{r}_{2}}}\] [As \[\eta =\] = constant and \[{{v}_{1}}={{v}_{2}}\]] \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{r}{4r}\]
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