A) \[C{{H}_{3}}COONa\]
B) \[NaCl\]
C) \[N{{H}_{4}}OOCC{{H}_{3}}\]
D) \[N{{H}_{4}}Cl\]
Correct Answer: D
Solution :
\[\text{N}{{\text{H}}_{\text{4}}}\text{Cl}\]is a salt of weak base \[(N{{H}_{4}}OH)\] and strong acid \[(HCl),\] thus undergoes cationic hydrolysis and provides \[{{\text{H}}^{\text{+}}}\]ions that make the solution acidic \[ie,\]pH is very less or less than 7. \[N{{H}_{4}}Cl+{{H}_{2}}O\xrightarrow{{}}N{{H}_{4}}OH+HCl\] or \[NH_{4}^{+}+{{H}_{2}}O\xrightarrow{{}}N{{H}_{4}}OH+{{H}^{+}}\]
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