A) \[-11\]
B) \[-44\]
C) \[-\text{ }55\]
D) \[~-22\]
Correct Answer: C
Solution :
Heat of neutralisation is the heat that evolved when one equivalent of acid is neutralised by one equivalent of a base. \[\because \]Milliequivalents of weak acid \[=400\times 0.2\] \[=80\]milliequivalents \[\therefore \]Equivalents of the acid \[=0.08\] equivalent. Since, heat evolved when 0.08 equivalent of acid is neutralised\[=4.4\text{ }kJ\] \[\therefore \]The heat evolved, when 1 equivalent is neutralised \[=\frac{4.4\times 1}{0.08}\] \[=55\,kJ\,\text{equi}{{\text{v}}^{-1}}.\]
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