A) \[{{F}_{2}}>C{{l}_{2}}>B{{r}_{2}}>{{I}_{2}}-\]Oxidising agent
B) \[N{{H}_{3}}>P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}>Bi{{H}_{3}}-\]Basic property
C) \[F>Cl>Br>I-\]Electron gain enthalpy
D) \[C>Si>Ge>Sn-\]Ability to form p-p bond
Correct Answer: C
Solution :
Generally, the electron gain enthalpy decreases as the number of shells increases but the electron gain enthalpy of fluorine is lesser than that of chlorine. This is because of smaller size of fluorine, due to which the incoming electron experience a greater force of repulsion and to overcome the repulsive force, some energy is used. Thus, the correct order of electron gain enthalpy is \[Cl>F>Br>I\]
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