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J & K CET Engineering J and K - CET Engineering Solved Paper-2012

  • question_answer
    A bar magnet is placed upright on a floor (so that the axis of the magnet is vertical). A copper ring is held above the magnet, with its plane horizontal and released. The copper ring falls in such a manner that its axis always coincides with that of the magnet. What will be the acceleration with which the ring will fall? Acceleration due to gravity is \[10m/{{s}^{2}}\].

    A)  \[10m/{{s}^{2}}\]

    B)  Less than \[10m/{{s}^{2}}\]

    C)  More than \[10m/{{s}^{2}}\]

    D) the answer will depend upon which pole of the magnet is up

    Correct Answer: B

    Solution :

    The acceleration with which the ring will fall will be class than \[10\text{ }m/{{s}^{2}}\].


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