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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        For the reaction,\[PC{{l}_{3}}(g)+C{{l}_{2}}(g)PC{{l}_{5}}(g)\]the value of\[{{K}_{c}}\]at\[250{}^\circ C\]is 26. The value of\[{{K}_{p}}\] at this temperature will be

    A)  0.0006                 

    B)  0.46

    C)  0.57                                      

    D)  0.83

    Correct Answer: A

    Solution :

                    \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\]\[=26{{(82.05\times 523)}^{-1}}\]\[=\frac{26}{82.05\times 523}=6.06\times {{10}^{-4}}atm\]


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