JCECE Engineering JCECE Engineering Solved Paper-2005

  • question_answer
    The coagulating power of an electrolyte for arsenious sulphide decreases in the order:

    A) \[N{{a}^{+}}<A{{l}^{3+}}<B{{a}^{2+}}\]

    B) \[PO_{4}^{3-}<SO_{4}^{2-}<C{{l}^{-}}\]

    C)  \[Cl<SO_{4}^{2-}<PO_{4}^{3-}\]

    D)   \[A{{l}^{3+}}<B{{a}^{2+}}<N{{a}^{+}}\]

    Correct Answer: D

    Solution :

    Key Idea: According to Hardy Schulz rule, the coagulating power of electrolyte increases with charge ion. \[\because \]\[A{{s}_{2}}{{S}_{3}}\]is negatively charged colloid and so it will be coagulated by cations. \[\therefore \]Correct order of coagulating power for \[A{{s}_{2}}{{S}_{3}}\] is\[A{{l}^{3+}}<B{{a}^{2+}}<N{{a}^{+}}\]


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