A) \[{{C}_{1}}{{V}_{1}}={{C}_{2}}{{V}_{2}}\]
B) \[{{V}_{1}}={{V}_{2}}\]
C) \[{{C}_{1}}={{C}_{2}}\]
D) \[\frac{{{C}_{1}}}{{{V}_{1}}}=\frac{{{C}_{2}}}{{{V}_{2}}}\]
Correct Answer: B
Solution :
When a conductor of capacitance C is charged, it acquires a potential \[V=\frac{q}{C}\] When connected in parallel, equivalent capacitance of combination is \[C'={{C}_{1}}+{{C}_{2}}\] Also, energy flow \[\left( E=\frac{1}{2}C'{{V}^{2}} \right)\] will not take place, if potential across capacitors is same.
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