question_answer

The mass of a lift is\[500\,\,kg\]. When it ascends with an acceleration of \[2m/{{s}^{2}}\] the tension in the cable will be:\[(g=10\,\,m/{{s}^{2}})\]

A) \[6000\,\,N\]                    

B) \[5000\,\,N\]

C)  \[4000\,\,N\]                   

D)  \[1000\,\,N\]

Correct Answer: A

Solution :

The resultant acceleration \[(a)\] is provided by resultant of tension \[(T)\] and weight\[(mg)\]. Therefore,                 \[T-mg=ma\] \[\Rightarrow \]                        \[T=m(g+a)\] Given\[m=500\,\,kg,\,\,g=10\,\,m/{{s}^{2}},\,\,a=2\,\,m/{{s}^{2}}\] \[\therefore \]          \[T=500(10+2)\] \[\Rightarrow \]                       \[T=6000\,\,N\]