A) \[{{109}^{o}}28\]
B) \[{{107}^{o}}10\,\]
C) \[104.5{{\,}^{o}}\]
D) \[{{92}^{o}}\]
Correct Answer: C
Solution :
The H-O-H bond angle in water is \[{{104}^{0}}28,\] in accordance with the VSEPR prediction of slightly less than tetrahedral due to the presence of lone pairs of electrons on oxygen atom. Thus the orbitals used for bonding by O are close to \[\text{s}{{\text{p}}^{\text{3}}}\]hybrids.
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