A) carbon dioxide
B) chlorine
C) iodine
D) sulphur dioxide
Correct Answer: B
Solution :
\[\text{C}{{\text{l}}_{\text{2}}}\]being a stronger oxidising agent, oxidises bromide present in the mother liquor to \[\text{B}{{\text{r}}_{2}}.\] \[\underset{\text{from}\,\text{mother}\,\text{liquor}}{\mathop{2B{{r}^{-}}}}\,+C{{l}_{2}}\xrightarrow{{}}\underset{bromide}{\mathop{B{{r}_{2}}}}\,+2C{{l}^{-}}\]
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