JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    The motion of a particle executing SHM in one dimension is described by \[x=-0.3\sin \left( t+\frac{\pi }{4} \right).\] where, \[x\] is in metre and t in second. The frequency of oscillation in Hz is

    A)  3

    B)  \[\frac{1}{2\pi }\]

    C)  \[\frac{\pi }{2}\]

    D)  \[\frac{1}{\pi }\]

    Correct Answer: B

    Solution :

     \[x=-0.3\sin \left( t+\frac{\pi }{4} \right)\] \[x={{x}_{0}}\sin (\omega t+o|)\] \[{{x}_{0}}=0.3,\omega =1\]and \[\text{o }\!\!|\!\!\text{ =}\frac{\pi }{4}\] \[2\pi f=1\] \[f=\frac{1}{2\pi }\]


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