A) 100 J
B) 931.1 kcal
C) 931.1 MeV
D) \[{{10}^{7}}erg\]
Correct Answer: C
Solution :
1amu\[=1.67\times {{10}^{-24}}g\] Energy equivalent to this mass can be calculated by using the relation; \[E=m{{c}^{2}}\] Here \[m=1.67\times {{10}^{-24}}g\] \[c=3\times {{10}^{10}}cm\,{{\sec }^{-1}}\] \[\therefore \] \[E=1.67\times {{10}^{-24}}\times {{(3\times {{10}^{10}})}^{2}}ergs\] \[=\frac{1.503\times {{10}^{-3}}}{{{10}^{7}}}J\] \[=1.503\times {{10}^{-10}}J\] Now, \[1.6\times {{10}^{-19}}J=1\text{ }eV\] \[1J=\frac{1}{1.6\times {{10}^{-19}}}eV\] \[=6.25\times {{10}^{18}}eV\] \[\therefore \] \[1.503\times {{10}^{-10}}J\] \[=6.25\times {{10}^{18}}\times 1.503\times {{10}^{-10}}eV\] \[=9.393\times {{10}^{8}}eV\] \[\therefore \]1 amu\[=939.3MeV.\]
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