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Manipal Medical Manipal Medical Solved Paper-2007

  • question_answer
    A solid compound X on heating gives\[C{{O}_{2}}\]gas and a residue. The residue mixed with water forms on passing an excess of\[C{{O}_{2}}\]through T in water, a clear solution, Z is obtained. On boiling Z compound X is reformed. The compound X is

    A)  \[Ca{{(HC{{O}_{3}})}_{2}}\]    

    B)  \[CaC{{O}_{3}}\]

    C)  \[N{{a}_{2}}C{{O}_{3}}\]       

    D)  \[{{K}_{2}}C{{O}_{3}}\]

    Correct Answer: B

    Solution :

     Compound X is\[CaC{{O}_{3}}\]. \[\underset{X}{\mathop{CaC{{O}_{3}}}}\,\xrightarrow[{}]{\Delta }\underset{\operatorname{Re}sidue}{\mathop{CaO}}\,+C{{O}_{2}}\uparrow \] \[\underset{\operatorname{Re}sidue}{\mathop{CaO}}\,+{{H}_{2}}O\xrightarrow[{}]{}\underset{Y}{\mathop{Ca{{(OH)}_{2}}}}\,\] \[\underset{Y}{\mathop{Ca{{(OH)}_{2}}}}\,+\underset{Excess}{\mathop{C{{O}_{2}}}}\,+{{H}_{2}}O\xrightarrow[{}]{{}}\underset{Z}{\mathop{Ca{{(HC{{O}_{3}})}_{2}}}}\,\] \[Ca{{(HC{{O}_{3}})}_{2}}\xrightarrow{\Delta }\underset{X}{\mathop{CaC{{O}_{3}}}}\,+{{H}_{2}}O+C{{O}_{2}}\uparrow \]


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