A) sucrose nitrate
B) adipicacid
C) oxalic acid
D) citric acid
Correct Answer: C
Solution :
Sucrose reacts with cone.\[HN{{O}_{3}}\]to give oxalic acid. \[{{C}_{12}}{{H}_{22}}{{O}_{11}}+18[O]\xrightarrow[{}]{Conc.\text{ }HN{{O}_{3}}}\] \[\underset{COOH}{\overset{COOH}{\mathop{6|}}}\,+5{{H}_{2}}O\]
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