A) constant
B) four times
C) two times
D) half
Correct Answer: C
Solution :
\[W=\frac{D\lambda }{d}\]\[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{d}_{2}}}{{{d}_{1}}}=\frac{1}{2}{{W}_{2}}=2{{W}_{1}}\]
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