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MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    The magnetic flux\[\phi \]in a closed circuit of resistance\[10\,\Omega \]. varies with time t (in second) as\[\pi =(4{{t}^{2}}-5t+1)Wb\]. The magnitude of induced current at\[t=0.20s\] is

    A)  0.12 A                  

    B)  0.38 A

    C)  0.34 A                  

    D)  0.12 A

    Correct Answer: C

    Solution :

                    Induced potential is given by \[\varepsilon =-\frac{d\phi }{dt}=-\frac{d}{dt}(4{{t}^{2}}-5t+1)\] \[=(2\times 4t-5)=5-8t\] At           \[t=0.20s\] \[=3.4V\] So, induced current will be                 \[I=\frac{\varepsilon }{R}=\frac{3.4}{10}=0.34A\]


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