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NEET NEET SOLVED PAPER 2016 Phase-I

  • question_answer
    The ratio of escape velocity at earth \[({{v}_{e}})\] to the escape velocity at a planet \[({{v}_{p}})\] whose radius and mean density are twice as that of earth is :-                                                                                                        

    A)  1 : 2                                      

    B)  \[1:2\sqrt{2}\]

    C)  1 : 4                                      

    D)  \[1:\sqrt{2}\]

    Correct Answer: B

    Solution :

                     \[{{V}_{e}}=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2G}{R}.\left( \frac{4}{3}\pi {{R}^{3}}\rho  \right)}\propto R\sqrt{\rho }\]                 \[\therefore \]\[\text{Ratio}\,\,\text{=}\,\,1:2\sqrt{2}\]


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