A) \[E=\,\frac{hc}{\lambda }\]
B) \[E=\,\frac{1}{2}m{{u}^{2}}\]
C) \[P=\,\frac{E}{2v}\]
D) \[E=\,\frac{1}{2}m{{c}^{2}}\]
Correct Answer: A
Solution :
\[E=\frac{hc}{\lambda }\] where\[\lambda \] is wavelength of photon.
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