RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    The phase difference in R-C circuit will be

    A)  \[\phi ={{\tan }^{-1}}\left( \frac{1}{\omega CR} \right)\]

    B)  \[\phi ={{\tan }^{-1}}\left( \frac{\omega }{RC} \right)\]

    C)  \[\phi ={{\tan }^{-1}}\left( \frac{RC}{\omega } \right)\]

    D)  \[\phi ={{\tan }^{-1}}\sqrt{\frac{\omega }{RC}}\]

    Correct Answer: A

    Solution :

     \[\phi ={{\tan }^{-1}}\left( \frac{{{X}_{C}}}{R} \right)\] \[={{\tan }^{-1}}\left( \frac{1}{\omega RC} \right)\]     \[\left( \because {{X}_{C}}=\frac{1}{\omega C} \right)\]


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