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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    The fundamental frequency of open pipe is n. The tube is immersed in water by placing in a vertical position so that its half part remain in the water. Now the fundamental frequency of air column will be

    A)  \[\frac{n}{2}\]

    B)  \[\frac{2n}{4}\]

    C)  \[n\]

    D)  \[2n\]

    Correct Answer: C

    Solution :

     When the half part of open pipe immersed the water, then its will be change closed of halflength. \[n=\frac{v}{2l}\] \[n'=\frac{v}{4(l/2)}\] \[=\frac{2V}{4l}\] \[=\frac{v}{2l}=n\]


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