A) \[SO_{3}^{2-},CrO_{4}^{2-}\]
B) \[S{{O}_{3}},CrO_{4}^{2-}\]
C) \[S{{O}_{2}},CrO_{4}^{2-}\]
D) \[S{{O}_{2}},C{{r}_{2}}O_{7}^{2-}\]
Correct Answer: B
Solution :
Let the oxidation number of S is\[x\]in\[S{{O}_{3}},\] then \[x+3(-2)=0\] \[x-6=0\] \[x=+6\] Let the oxidation number of Cr is\[x\]in\[CrO_{4}^{2-}\] then \[x+4(-2)=-2\] \[x-8=-2\] \[x=-2+8\] \[=+6\] Hence, the oxidation number of sulphur and chromium in\[S{{O}_{3}}\]and\[CrO_{4}^{2-}\]is same, ie, 6.
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