A) \[\sqrt{p}\]
B) \[\frac{1}{\sqrt{p}}\]
C) \[{{p}^{2}}\]
D) \[p\]
Correct Answer: B
Solution :
\[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}\] \[{{K}_{p}}=\frac{{{x}^{2}}p}{{{(1-x)}^{2}}}\] If \[x<<1\]mole then \[{{K}_{p}}={{x}^{2}}p\] \[x\propto \frac{1}{\sqrt{p}}\] where,\[{{K}_{p}}=\]equilibrium constant
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