RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The square coil of turn 60 has length 20 cm and breath 10 cm is rotating rate of 1800 rev/min in uniform magnetic field of intensity 0.5 T. the maximum emf of coil will be

    A)  98 V            

    B)  110 V

    C)  113 V           

    D)  118 V

    Correct Answer: C

    Solution :

     \[{{E}_{\max }}=NA\omega B=NAB.2n\pi \] \[=60\times (20\times 10\times {{10}^{-4}})\times 0.5\times 2\pi \times \frac{1800}{60}\] \[=113V\]


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