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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The oxidation number of Cr in\[{{K}_{2}}Cr{{O}_{4}}\]is

    A)  +3             

    B)  \[-3\]

    C)  +6             

    D)  \[-6\]

    Correct Answer: C

    Solution :

     Let the oxidation number of Cr in\[{{R}_{2}}Cr{{O}_{4}}\]is\[x\]. \[2+(1)+x+4(-2)=0\] \[2+x-8=0\] \[x=8-2\] \[=6\]


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