RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    The resistor of resistance R is connected to 25 V supply and heat produced in it is 25 J/s. The value of R is

    A)  225\[\Omega \]           

    B)  1\[\Omega \]

    C)  25\[\Omega \]            

    D)  50\[\Omega \]

    Correct Answer: C

    Solution :

     Power,   \[P=\frac{{{V}^{2}}}{R}\] \[\Rightarrow \] \[R=\frac{{{V}^{2}}}{p}=\frac{25\times 25}{25}=25\,\Omega \]


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