A) \[+6\]
B) \[+5\]
C) \[-7\]
D) \[+8\]
Correct Answer: A
Solution :
\[{{H}_{2}}{{S}_{2}}{{O}_{8}}\](perdisulphuric acid or Marshal acid) \[H-O-\underset{O}{\mathop{\underset{||}{\mathop{\overset{O}{\mathop{\overset{||}{\mathop{S}}\,}}\,}}\,}}\,-\overset{-1}{\mathop{O}}\,-\overset{-1}{\mathop{O}}\,-\underset{O}{\mathop{\underset{||}{\mathop{\overset{O}{\mathop{\overset{||}{\mathop{S}}\,}}\,}}\,}}\,-O-H\] \[(+1\times 2)+2x+(-1\times 2)+(-2\times 6)=0\] \[2+2x-2-12=0\] \[2x-12=0\] \[x=6\]
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