RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    The formula of brown ring complex compound in \[[Fe{{({{H}_{2}}O)}_{5}}N{{O}^{+}}]S{{O}_{4}},\] What is the oxidation number of \[Fe\]?

    A)  \[+1\]                                                  

    B)  \[+3\]

    C)  \[+2\]                  

    D)         \[-1\]

    Correct Answer: A

    Solution :

    \[[Fe{{({{H}_{2}}O)}_{5}}N{{O}^{+}}]S{{O}_{4}}\] \[x+0+1-2=0\]                 \[x=+1\]


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