question_answer

\[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{SOC{{l}_{2}}}A\] \[\xrightarrow{LiAl{{H}_{4}}\,(ter.\,but.\,oxide)}B\xrightarrow{\underset{C{{H}_{2}}OH}{\overset{C{{H}_{2}}OH}{\mathop{|}}}\,}C.\] C is:

A)  

B)  \[C{{H}_{3}}C{{H}_{2}}COCl\]

C)  \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\]

D)  None of the above

Correct Answer: A

Solution :

The reaction occurs as follows: \[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{SOC{{l}_{2}}}\underset{(A)}{\mathop{C{{H}_{3}}C{{H}_{2}}}}\,COCl\]