A) electron
B) proton
C) both (a) and (b)
D) none of these
Correct Answer: A
Solution :
According to de-Broglie hypothesis, wavelength, \[\lambda =\frac{h}{p}\] where \[h\] is Plancks constant. Also, \[p=mv\] \[\therefore \] \[\lambda =\frac{h}{mv}\] \[\Rightarrow \] \[\lambda \propto \frac{1}{n}\] Mass of electron is \[9.1\times {{10}^{-31}}\,\,kg\] and of proton is \[1.6\times {{10}^{-27}}\,\,kg\], hence mass of electron is less than that of proton, so electron will have greater wavelength.
You need to login to perform this action.
You will be redirected in
3 sec
