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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    A block B is pushed momentarily along a horizontal surface with an initial velocity v. If \[\mu \] is the coefficient of sliding friction between B and the surface, block B will come to rest after a time

    A)  \[\frac{v}{gu}\]                                               

    B)  \[\frac{gu}{v}\]

    C)  \[\frac{g}{v}\]                  

    D)         \[\frac{v}{g}\]

    Correct Answer: A

    Solution :

    Block \[B\] will come to rest, if force applied to it will vanish due to frictional force acting between block \[B\] and surface,\[ie,\]                 force applied = frictional force \[ie,\]    \[\mu mg=ma\] or            \[\mu mg=m\left( \frac{v}{t} \right)\] or            \[t=\frac{v}{\mu g}\]


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