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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.20. The amount of heat generated in 5 s is V = 4.2 J/cal and \[g=9.8\,m/{{s}^{2}}\])

    A)  9.33 cal               

    B)         10.21 cal

    C)  12.67 cal             

    D)         13.34 cal

    Correct Answer: A

    Solution :

    Work done = Force\[\times \]Displacement \[W=\mu \,\,mg\times (v\times t)\] \[W=(0.2)\times 2\times 9.8\times 2\times 5\] \[W=39.2\,\,J\] Heat generated,\[Q=\frac{W}{J}\]                                 \[=\frac{39.2}{4.2}\]                                 \[=9.33\,\,cal\]


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