A) \[\Delta {{G}^{o}}=-{{K}_{c}}\log RT\]
B) \[\Delta {{G}^{o}}=-RT\log {{K}_{c}}\]
C) \[\Delta {{G}^{o}}=-\frac{\log RT}{{{K}_{c}}}\]
D) \[\Delta {{G}^{o}}=-\log \frac{{{K}_{c}}}{RT}\]
Correct Answer: B
Solution :
Relationship between standard free energy \[(\Delta {{G}^{o}})\] and equilibrium constant \[({{K}_{c}})\] at temperature \[T\] is given by \[\Delta {{G}^{o}}=RT\ln {{K}_{c}}\] or \[\Delta {{G}^{o}}=-RT{{\log }_{e}}{{K}_{c}}\]
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