A) laevo-rotatory
B) meso-compound
C) dextro-rotatory
D) racemic mixture
Correct Answer: D
Solution :
Since during the reaction, a chiral carbon is created and further since the\[C{{N}^{-}}\]ion can attack the planar aldehyde group both from the top and the bottom face with equal ease, therefore, a\[50:50\]mixture of the two enantiomers e., a racemic mixture is obtained.
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