A) Decreasing the temperature
B) Increasing the temperature
C) Dissolving \[NaCl\] crystals in the equilibrium mixture
D) Dissolving \[N{{H}_{4}}N{{O}_{3}}\] crystals in the equilibrium mixture
Correct Answer: B
Solution :
\[N{{H}_{4}}Cl(s)\xrightarrow{{}}NH_{4}^{+}(aq)+C{{l}^{-}}(aq)\] \[\Delta H=+3.5kcal/mol\] This is the endothermic reaction hence, increasing the temperature will shift the equilibrium to the right.You need to login to perform this action.
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