VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    If the roots of the equations \[{{x}^{2}}+ax+b=0\]are c and d, then one of the roots of the equation\[{{x}^{2}}+(2c+a)x+{{c}^{2}}+ac+b=0\]is

    A)  \[c\]

    B)  \[d-c\]

    C)  \[2d\]

    D)  \[2c\]

    Correct Answer: B

    Solution :

    Given, \[f(x)={{x}^{2}}+ax+b,\]then \[f(x+c)={{(x+c)}^{2}}+a(x+c)+b\] \[={{x}^{2}}+(2c+a)x+{{c}^{2}}+ac+b\] Which show roots of \[f(x)\]are transformed to \[(x-c)\]i.e., roots of \[f(x+c)=0\]are \[c-c\]and \[d-c.\] Hence, one of the roots of the equation \[f(x+c)\]is\[(d-c).\]


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