resistor in each
of the following circuits :
(i)
a 6 V battery in series with 1 and 2 resistors, and
(ii) a 4 V battery in parallel with 12 and 2 resistors.
Answer:
(i) Since 6 V battery is in series with 1
and 2 resistors, current in the
circuit,
I
= 
Power
used in 2 resistor, P1 = I2R = (2A)2 ×
2 = 8W
(ii)
Since 4 V battery is in parallel with 12 and 2 resistors, pd across 2 resistor, V = 4V.
Power
used in 2 resistor, P2 = 
Clearly,
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