Answer:
We are given that, diameter of the wire, D = 0.5 mm = 0.5 × 10?3 m resistivity of copper,
= 1.6 × 10?6 ohm cm = 1.6 × 10?8 ohm m required resistance, R = 10 ohm
As
R =
,
=
[A =
=
]
or
m = 112.7 m
Since, R
=
, R
1/D2. When D is doubled, R becomes
times.
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