Answer:
(a)
Let us assume that the resistance of each bulb be R. The circuit diagram in two
cases may be drawn as given below
Equivalent resistance in series combination, voltage =V Let
current through each bulb in series combination be . By Ohm's law,
So, power consumption of each bulb in series combination.
?(i)
For parallel circuit, (1)
The resistance of each bulb = R
Voltage across each bulb = V
[same
voltage in parallel combination]
Power
consumption of each bulb in parallel combination ?(ii)
From Eqs.
(i) and (ii), we have
Therefore, each bulb in parallel combination glows 3 times
brighter to that of each bulb in series combination.
(b) When one bulb gets fused in both the circuit, then in
series combination, circuit gets broken and current stops flowing and remaining
bulb don't glow. Whereas in parallel combination, same voltage continue to act
on the remaining voltage and hence, other bulbs continue to glow with same
brightness.
You need to login to perform this action.
You will be redirected in
3 sec