Answer:
\[O_{2}^{+}:15\]
\[KK\sigma {{(2s)}^{2}}{{\sigma
}^{*}}{{(2s)}^{2}}\sigma {{(2{{p}_{z}})}^{2}}\pi {{(2{{p}_{x}})}^{2}}\pi
{{(2{{p}_{y}})}^{2}}{{\pi }^{*}}{{(2{{p}_{x}})}^{1}}\]
Bond
order \[=\frac{8-3}{2}=2.5\]It is paramagnetic
\[O_{2}^{-}:17\]\[KK\sigma
{{(2s)}^{2}}{{\sigma }^{*}}{{(2s)}^{2}}\sigma (2{{p}_{z}})\pi
{{(2{{p}_{x}})}^{2}}\]
\[\pi
{{(2{{p}_{y}})}^{2}}{{\pi }^{*}}{{(2{{p}_{x}})}^{2}}{{\pi
}^{*}}{{(2{{p}_{y}})}^{1}}\]
Bond
order = \[\frac{8-5}{2}=1.5\]It is paramagnetic
Bond
order \[\propto \] Bond energy
Thus,
Bond energy of \[O_{2}^{+}\]> Bond energy of\[O_{2}^{-}\].
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